How to calculate volume of chlorine gas at stp?
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The volume of all the gases at stp is 22.4 L .
For different moles of gasea compare the volume 22.4 L u will get the required answer
For different moles of gasea compare the volume 22.4 L u will get the required answer
Answered by
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Answer:
since, W= molor mass x I x T /
96500 x n.factor
W= 23x1x965 /
96500x1
ans 1. W= .23 gm (weight of Na at cathode)
since .01 mole of both elements participated in reaction...
here we know volume of every gas is 22.4 lt at stp
therefore, vol of Cl at anode is 22.4 x .01 = .224 lt.
Explanation:
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