Question

How to calculate volume of coarse aggregate in concrete?

Answer 1

hey mate here's your answer......

Let us consider M20 concrete mix - 1:1.5:3

Total Volume = 1+1.5+3 = 5.5

Consider, Wet volume = 1m^3

Dry Volume =1.54x1 =1.54 m^3 (54% increases)

Cement:

Quantity of cement In Cubic metres = 1x1.54/5.5 = 0.28m^3

Quantity of cement in kg = 1x1.54/5.5x1440 = 403.2 kg ( Density of cement = 1440 kg/m^3 )

Total no. of cement bags required = 403.2/50 = 8.064 bags

Sand:

Quantity of sand in Cubic metre = 1.5x1.54/5.5 = 0.42 m^3

Quantity of sand in kg = 1.5x1.54/5.5x1500 = 630 kg ( Density of sand = 1500 kg/m^3 )

Quantity of sand in Cubic feet = 1.5x1.54/5.5x35.3147 = 14.83 cu.ft

Aggregates:

Quantity of aggregate in Cubic metre = 3x1.54/5.5 = 0.84 m^3

Quantity of aggregate in kg = 3x1.54/5.5x1450 = 1218 kg ( Density of aggregate = 1450 kg/m^3 )

Quantity of aggregate in cubic feet = 3x1.54/5.5x35.3147 = 29.66 cu.ft

Water:

For M20, 30 liters of water per 50kg cement should be used.

Total amount of water required = 30x403.2/50 = 241.92 litres.

....hope this helps you.....