Question

How to call a function using a pointer?​

Answer 1

The call by pointer method of passing arguments to a function copies the address of an argument into the formal parameter. Inside the function, the address is used to access the actual argument used in the call. This means that changes made to the parameter affect the passed argument.

To pass the value by pointer, argument pointers are passed to the functions just like any other value. So accordingly you need to declare the function parameters as pointer types as in the following function swap(), which exchanges the values of the two integer variables pointed to by its arguments.

// function definition to swap the values.

void swap(int *x, int *y) {

int temp;

temp = *x; /* save the value at address x */

*x = *y; /* put y into x */

*y = temp; /* put x into y */

return;

}

Have a nice day mate ❤️

Answer 2

$\huge \purple A \purple N \purple s \purple W \purple e \purple \R :-$

• You can declare the function pointer as follows: bool (funptr*)(); Which says we are declaring a function pointer to a function which does not take anything and return a bool. bool (*FuncPtr)() FuncPtr = A; FuncPtr();