Question

how to choose x values for ×^2-x-12

Answer 1

Hello dear..your answer is here

x^2-x-12=0

x^2-4x+3x-12=0

x (x-4)+3 (x-4)=0

(x-4)(x+3)=0

x=4 and -3

Hope it helps

Answer 2

Here is ur answer!!

➡️ X²-x-12
= (x+3)(x-4)
x= -3 atau x= 4 ✔️

May be usefull ^_^