Question

How to complete the chapter "Quadratic Equations" of "RD Sharma" in 2 days ❓❓❓❓❓❓❓❓❓❓

PLEASE DON'T ANSWER ANY IRRELEVANT THING SUCH AS "I don't know", " Impossible" etc etc. ​

Answer 1

Answer:

hi friend

Step-by-step explanation:

mate you can easily complete your chapter by followings ways :-

-Focus on study.

-Do easy question first then harder one.

- give as less time on playing as you can.

- solve questions by applying formula.

- give more time to study

hope it's helpful......

please mark me brilliant.......

Answer 2

Answer:

Answer:

Perimeter of rectangle is 136 cm.

Step-by-step explanation:

Given :-

Area of rectangle and area of square are equal.

Perimeter of square is 64 cm.

Breadth of rectangle is 4 cm.

To find :-

Perimeter of rectangle.

Solution :-

• First we will find side of square using perimeter.

• Area of square and area of rectangle are equal. So, then we will find length of rectangle using area of rectangle.

• Then, Finally we will find required perimeter.

________________________________

Perimeter of square = 4 × side

\longrightarrow⟶ 64 = 4 × side

\longrightarrow⟶ 64/4 = side

\longrightarrow⟶ side = 16

Side of square is 16 cm

Area of square = Side × Side

\longrightarrow⟶ Area = 16 × 16

\longrightarrow⟶ Area = 256

Area of square is 256 cm².

It is given that,

Area of rectangle is equal to area of square.

So, Area of rectangle is 256 cm².

Area of rectangle = length × breadth

\longrightarrow⟶ 256 = Length × 4

\longrightarrow⟶ 256/4 = Length

\longrightarrow⟶ Length = 64

Length of rectangle is 64 cm.

Now,

Perimeter of rectangle = 2(Length + Breadth)

\longrightarrow⟶ Perimeter = 2 × (64 + 4)

\longrightarrow⟶ Perimeter = 128 + 8

\longrightarrow⟶ Perimeter = 136

Therefore,

Perimeter of rectangle is 136 cm.