how to compute sigma 2^n
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Hello user☺☺
It will be..
2^1 +2^2 +2^3 + ................+ 2^n
Here , we can see the formation of a G.P. with a = 2 and r =2
So,
Sn = a(r^n - 1)/r-1
2(2^n - 1)/2-1
2(2^n - 1)
Hope this will help☺☺
It will be..
2^1 +2^2 +2^3 + ................+ 2^n
Here , we can see the formation of a G.P. with a = 2 and r =2
So,
Sn = a(r^n - 1)/r-1
2(2^n - 1)/2-1
2(2^n - 1)
Hope this will help☺☺
rahuladya1819:
thanx
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