how to construct 7 rows & 7 columns square such that row-wise / column-wise /diagonal-wise
sum remains same & is = 175
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Hi !
It is called a magic square and there are various tricks to make your custom magic square. I have memorised 3*3 magic square. For 7*7, you can find it in various maths books. You can find the common sum of the diagonals/columns/rows in the following way if the magic square has consecutive numbers starting from 1.:-
let number of columns=rows=x
sum=
You can find the methods to create magic squares in other books/e-books as it is impossible to explain here.
It is called a magic square and there are various tricks to make your custom magic square. I have memorised 3*3 magic square. For 7*7, you can find it in various maths books. You can find the common sum of the diagonals/columns/rows in the following way if the magic square has consecutive numbers starting from 1.:-
let number of columns=rows=x
sum=
You can find the methods to create magic squares in other books/e-books as it is impossible to explain here.
pmg2004:
Row one 30 39 48 1 10 19 28
Rowwise 30 39 48 1 10 19 28 19 38 47 7 9 18 27 29 ; 46 6 8 17 26 35 37 ; 5 14 16 25 34 36 45 ; 13 15 24 33 42 44 4 ; 21 23 32 41 43 3 12 ; 22 31 40 49 2 11 20 28
30 39 48 1 10 19 28 * 38 47 7 9 18 27 29 * 46 6 8 17 26 35 37 * 5 14 16 25 34 36 45 * 13 15 24 33 42 44 4 * 21 23 32 41 43 3 12 * 22 31 40 49 2 11 20 ....Magic Square will give total of 175 for each row / column / diagonal.. pl.check..
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Answer:
addition any 5 which have 7 rows and coloums
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