how to construct a 5cm equilateral triangle
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Let ABC be the ∆ ...... (1)Draw AB as base = 5 cm......... (2) Draw perpendicular bisector of AB....... (3) Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector........ (4) Do the same with point B and wherever those arcs meet name that point C......... (5) Thus ABC is the required ∆.
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it's too easy.
take a length of 5 cm and construct three side through it.
ur triangle is ready
take a length of 5 cm and construct three side through it.
ur triangle is ready
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