How to construct a ΔABC in which AB=2cm, BC=3.5cm, and angle C=80° ?
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Take your notebook and start doing the construction of ∆ABC by following the steps given below:-
1) Using ruler draw a line segment measuring 3.5cm. Mark this line segment as BC.
2) Take your protractor and keep on C in. Look at the left hand side of 90°. You will find an angle 110°. Below it is written 80°. Mark that point (110° below written 80°). Join C with that point and extend that line.
3) Take your compass and keep it on the ruler and measure 2cm.
4) Take it and put on B and draw an arc which cuts the extended line ( which you made at step 2) at a point. . Mark that point as A.
5) Join AB and you will get the required ∆.
1) Using ruler draw a line segment measuring 3.5cm. Mark this line segment as BC.
2) Take your protractor and keep on C in. Look at the left hand side of 90°. You will find an angle 110°. Below it is written 80°. Mark that point (110° below written 80°). Join C with that point and extend that line.
3) Take your compass and keep it on the ruler and measure 2cm.
4) Take it and put on B and draw an arc which cuts the extended line ( which you made at step 2) at a point. . Mark that point as A.
5) Join AB and you will get the required ∆.
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