Question

how to construct a perpendicular bisector of a line?

Answer 1

.Place the compass at one end of line segment.
Adjust the compass to slightly longer than half the line segment length
Draw arcs above and below the line.
Keeping the same compass width, draw ar from other end of line.
Place ruler where the arcs cross, and draw the line segment.

Answer 2

$\huge{ \underline{ \underline{ \mathfrak{ \blue{ \sf{Perpendicular \: Bisector}}}}}}$

Firstly, what is a bisector?

In math, if a line bisects an angle by dividing that angle into two equal parts, it is called a bisector.

Secondly, what is a perpendicular bisector?

In perpendicular bisector, the line divides the angle into two equal parts perpendicularly.

*Perpendicular = 90°*

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Coming to the Construction,

• Draw a line AB with any radius, for now let's take 6cm.
• Taking more than half of the above taken radius, that is 6cm, we have to draw an arc.

Why should we take more than half?

Because if we taken less than half of the radius, then the arcs won't intersect. In our case if we take less than half that is less than 6cm, the arcs won't intersect.

• Taking A & B as centre, we've to draw 2 arcs both in the top and bottom.

Why two arcs?

Because when we draw two arcs, we get two intersection points. And when we join two intersection points, we get a line which will be our perpendicular bisector of line AB.

• After drawing the arcs by taking A as centre, we've to cut those arcs by taking B as centre.
• Now we have two intersection points, let's name them P & Q. The middle point on the line where the perpendicular bisector passes is named as M. Joining P & Q, we get a line PMQ.
• Line PMQ is the perpendicular bisector of line AB

Refer to the attachment for a picture of a perpendicular bisector.