how to construct a perpendicular to hypotenuse from vertex of triangle
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consider a triangle say abc
b is the right angle
cut an arc( any radius) on hypotenuse ac intersecting at two points (here m and n )
draw the perpendicular bisector of the line mn
the perpendicular bisector will pass through c
hence cd is the perpendicular
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..... see the adjoining fig .
.. plzz mark the ans as brainliest .... plzzz
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Step-by-step explanation:
1.Consider a right angle triangle say ΔABC, right angled at A
2.Draw an arc by considering C as center and AC as radius.
3.Similarly, draw an arc considering B as center and AB as radius.
4.They intersect at two points, one is at A and other is at D.
5.Join the points, A and D.
6.This is perpendicular to hypotenuse.
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