Question

how to construct a rhombus having two diagonals of measurement 4.4 cm. and 5cm. ? plzzzzzzzz tellll anyoneeee !!!!!

Answer 1

Answer:

Step-by-step explanation:

Construction of Rhombus  

Here you will understand how to construct a Rhombus; where only measure of its two diagonals are given.  

Example: Construct Rhombus PQRS, where two diagonals PR and SQ are 5 cm and 7 cm respectively.  

Solution: As per the given question  

PR & SQ are diagonals of Rhombus PQRS  

PR = 5 cm  

SQ = 7 cm  

Steps of construction are as follows:  

Step 1: Use ruler and draw line segment SQ of 7 cm, which is also one of the diagonal (as shown below):  

 

Step 2: Use compass and draw perpendicular bisector of line segment SQ (as shown below):  

Note: We construct perpendicular bisector because in Rhombus, diagonals are perpendicular bisector to each other.  

 

Step 3: Mark point of intersection (line segment and perpendicular bisector) as O (as shown below):  

 

Step 4: Use compass and 2.5 cm wide open. With O as center, draw two arcs, cutting perpendicular bisector at point P and R (as shown below):  

Note: Here we have chosen length of 2.5 cm because in Rhombus diagonals bisect each other at point of intersection. Since length of other diagonal is 5 cm (as given), so half of 5 cm is 2.5 cm  

 

Step 5: Use ruler and join points P & S, P & Q, S & R and R & Q. And we get the resultant Rhombus PQRS (as shown below)  

Answer 2

First draw 5 cm .Label as AB
Draw perpendicular on AB.
From A and B respectively,draw 4.4 cm upward and downward(arcs)
Join the arcs.
You get your rhombus.....
P.S Always draw a rough diagram before constructing