how to construct a square MNOP where the length of diagonal is 8 cm .plzz share the steps
Answers
Answered by
3
diagonal is 8cm so find the side of the square by Pythagoras theorem.
then you can construct it easily
then you can construct it easily
Answered by
3
Draw a line segment AC = 4.8 cm length
Now draw perpendicular bisector of AC. Let it intersect AC at point O.
With O as centre and radius equal to half of the length of the diagonal (2.4 cm) draw two arcs on either side of AC on the perpendicular bisector.
Mark the point of intersections of the arcs and perpendicular bisectors as B and C.
Join points A, B; points B, C; points C, D; points A, D.
Thus ABCD is the required square with length of diagonal 4.8 cm
Now draw perpendicular bisector of AC. Let it intersect AC at point O.
With O as centre and radius equal to half of the length of the diagonal (2.4 cm) draw two arcs on either side of AC on the perpendicular bisector.
Mark the point of intersections of the arcs and perpendicular bisectors as B and C.
Join points A, B; points B, C; points C, D; points A, D.
Thus ABCD is the required square with length of diagonal 4.8 cm
Similar questions