Question

How to Construct a trapezium ABCD in which AD||BC,angleB=60°,AB=5cm,BC=6.2cm and CD=4.8cm.

Answer 1

Heyaa....☺☺✌
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⏩To construct a trapezium ABCD, follow the given steps-

✔1. Draw BC = 6.2

✔2. Construct <B = 60, extend the line till 5cm and mark as A

✔3. Since ADllBC angle A = 120 ( 180-60 ) as they are corresponding angles and AB is the tranversal.

✔4. Now construct angle A = 120 and extend the line.

✔5. Draw CD = 4.8 cm

✔6. Now CD meets at the line extended by angle A

⏩So here is the required trapezium ABCD

[ If u have any doubt regarding this..feel free to ask me.]
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Thanks....☺☺✌

Answer 2

Step-by-step explanation:

here is your solution

• draw a line segment bc is equals to 6.2 CM
• heartbeat draw a re BA making an angle of 60 degree
• and cut off AB =5 cm
• from a draw a line AY parallel to BC
• with centre c and radius 4.8 CM draw an arc which intersect AY at D
• and join CD