how to construct a triangle which is having perimeter xy+yz+zy=10cm whose base angles are 30
degrees and 70 degrees
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Step 1: Draw a line segment=10cm.Name it AB.
Step 2:Draw the angle bisector of 30 degree at A and angle bisector of 70 degree at B.
Step 3: The angle bisector of 30 degree at A and angle bisector of 70 degree at B will join at a point name that point C.
Step 4: Now draw bisector of sides AC and BC.The bisectors will join the side AB at two points name these points X and Y.
Step 5:Join X and Y to C.name C as Y.
Result:the required triangle is XYZ
Step 2:Draw the angle bisector of 30 degree at A and angle bisector of 70 degree at B.
Step 3: The angle bisector of 30 degree at A and angle bisector of 70 degree at B will join at a point name that point C.
Step 4: Now draw bisector of sides AC and BC.The bisectors will join the side AB at two points name these points X and Y.
Step 5:Join X and Y to C.name C as Y.
Result:the required triangle is XYZ
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