Question

how to construct a triangle which is having perimeter xy+yz+zy=10cm whose base angles are 30
 degrees and  70 degrees

Answer 1

Step 1: Draw a line segment=10cm.Name it AB.
Step 2:Draw the angle bisector of 30 degree at A and angle bisector of 70 degree at B.
Step 3: The angle bisector of 30 degree at A and angle bisector of 70 degree at B will                  join at a point name that point C.
Step 4: Now draw bisector of sides AC and BC.The bisectors will join the side AB at two              points name these points X and Y.
Step 5:Join X and Y to C.name C as Y.
Result:the required triangle is XYZ