Question

how to construct an isosceles triangle PQR such that QR=7cm and bad angle is of 65 degree ?

Answer 1

Answer:

Case 1:

If angle QPR = 50 deg, then <PQR =<PRQ = (180–50)/2 = 65 deg.

In this case draw a line 7 cm long and name the ends Q and R. At Q make an angle RQP = 65 deg and again at R make an angle QRP = 65 deg. The PQR will be the desired triangle.

Case 2:

If <PQR = <PRQ = 50 deg, then <QPR = 180–50–50 = 80 deg.

In this case draw a line 7 cm long and name the ends Q and R. At Q make an angle RQP =50 deg and again at R make an angle QRP = 50 deg. The PQR will be the desired triangle.

Step-by-step explanation:

i hope this answer is useful

Answer 2

Step-by-step explanation:

We know that in an isosceles triangle two sides are equal.

so,PQ=QR=7cm

so lets draw QR of 7cm as base

next ,now put your protector on point Q and mark an angle of 65° with the help of pointQ

then ,draw line through point Q of any length

next,mark a point of 7 cm on that line and then join points P and R

this will be your required triangle