Math, asked by aknshaboruah2132, 11 months ago

How to construct square root of three by pythagoras theorem?

Answers

Answered by Akankshitha
0

HOPE THIS IS HELPFUL TO YOU

Step-by-step explanation:

One way you can do this is to use the Theorem of Pythagoras. Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.

One way you can do this is to use the Theorem of Pythagoras. Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.Using the compass, draw an arc of a circle with radius 2 and center C so that the arc intersects the first line at B. Draw the line segment CB.

One way you can do this is to use the Theorem of Pythagoras. Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.Using the compass, draw an arc of a circle with radius 2 and center C so that the arc intersects the first line at B. Draw the line segment CB.Now you have a right triangle with hypotenuse of length 2 units and one side of length 1 unit. Hence, by Pythagoras' Theorem

One way you can do this is to use the Theorem of Pythagoras. Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.Using the compass, draw an arc of a circle with radius 2 and center C so that the arc intersects the first line at B. Draw the line segment CB.Now you have a right triangle with hypotenuse of length 2 units and one side of length 1 unit. Hence, by Pythagoras' Theorem|CA| 2 + |AB| 2 = |BC| 2

One way you can do this is to use the Theorem of Pythagoras. Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.Using the compass, draw an arc of a circle with radius 2 and center C so that the arc intersects the first line at B. Draw the line segment CB.Now you have a right triangle with hypotenuse of length 2 units and one side of length 1 unit. Hence, by Pythagoras' Theorem|CA| 2 + |AB| 2 = |BC| 2That is

One way you can do this is to use the Theorem of Pythagoras. Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.Using the compass, draw an arc of a circle with radius 2 and center C so that the arc intersects the first line at B. Draw the line segment CB.Now you have a right triangle with hypotenuse of length 2 units and one side of length 1 unit. Hence, by Pythagoras' Theorem|CA| 2 + |AB| 2 = |BC| 2That is1 + |AB| 2 = 4

One way you can do this is to use the Theorem of Pythagoras. Draw a line. At a point A on the line construct a line which is perpendicular to the first line. Mark a point C on this line a distance of one unit from A.Using the compass, draw an arc of a circle with radius 2 and center C so that the arc intersects the first line at B. Draw the line segment CB.Now you have a right triangle with hypotenuse of length 2 units and one side of length 1 unit. Hence, by Pythagoras' Theorem|CA| 2 + |AB| 2 = |BC| 2That is1 + |AB| 2 = 4and thus |AB| 2 = 3 and |AB| is the square root of 3.

Answered by subbu96
0

this is badhaga thm we need to

find ATriangle

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