Question

how to contruct the centroid for APQR such that PQ=5cm ,PR=6cm and angleQPR =60°? I want it diagram format.​

Answer 1

Answer:

G is the centroid of the triangle

In ∆PQR, PQ = 5 cm, PR = 6 cm, ∠QPR = 60° Construction :

Step 1 : Draw ∆PQR with the given measurement

Step 2 : Draw perpendicular bisectors of any two sides (PQ and QR) to find the mid points of PQ and QR.

Step 3 : Draw medians PD and RE. Let them meet at G. Step 4 : G is the centroid of the given ∆PQR.