Question

How to convert equation of a plane from cartesian to vector form?

Answer 1

Explanation:

questions on the topic.

Solved Example for You

Question: Find the vector equation of a plane whose normal is by 5i^+3j^–2hatk and is at a distance of 9 / 38−−√ from the origin.

Answer: We have the normal vector as

n⃗ =5i^+3j^–2k^

To find the unit vector –

n^=n⃗ /|vecn|=5i^+3j^–2k^/(25+9+4)−−−−−−−−−−√=5i^+3j^–2k^/38−−√

Thus, we shall now use the formula for the vector equation of a plane in normal form and derive at the required equation –

n⃗ =r⃗ .(538−−√i^+338−−√j^+−238−−√