How to convert ethanal to 2-hydroxypropanoic acid ?
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Answered by
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Ethanol's formula is CH3-CH2-OH
So, CH3-CH2-OH + PI3 ------> CH3-CH2-I (ethyl iodide)
Then, CH3-CH2-I + KCN ------> CH3-CH2-CN (propionitrile)
And, CH3-CH2-CN + H(+)/H2O -------> CH3-CH2-COOH (propanoic acid)
Hence, CH3-CH2-COOH + Br2 + Red phosphorous --------> CH3-CH(Br)-COOH (2-bromopropanoic acid)
This reaction is called Hell-Volhard-Zelinsky reaction.
Now, CH3-CH(Br)-COOH + NaOH (aq) --------> CH3-CH(OH)-COOH (2-hydroxypropanoic acid or lactic acid)
This is how you convert Ethanol into 2-hydroxypropanoic acid.
So, CH3-CH2-OH + PI3 ------> CH3-CH2-I (ethyl iodide)
Then, CH3-CH2-I + KCN ------> CH3-CH2-CN (propionitrile)
And, CH3-CH2-CN + H(+)/H2O -------> CH3-CH2-COOH (propanoic acid)
Hence, CH3-CH2-COOH + Br2 + Red phosphorous --------> CH3-CH(Br)-COOH (2-bromopropanoic acid)
This reaction is called Hell-Volhard-Zelinsky reaction.
Now, CH3-CH(Br)-COOH + NaOH (aq) --------> CH3-CH(OH)-COOH (2-hydroxypropanoic acid or lactic acid)
This is how you convert Ethanol into 2-hydroxypropanoic acid.
Answered by
2
Answer:
CH3-CH2-OH + PI3 ------> CH3-CH2-I (ethyl iodide)
Then, CH3-CH2-I + KCN ------> CH3-CH2-CN (propionitrile)
And, CH3-CH2-CN + H(+)/H2O -------> CH3-CH2-COOH (propanoic acid)
Hence, CH3-CH2-COOH + Br2 + Red phosphorous --------> CH3-CH(Br)-COOH (2-bromopropanoic acid)
This reaction is called Hell-Volhard-Zelinsky reaction.
Now, CH3-CH(Br)-COOH + NaOH (aq) --------> CH3-CH(OH)-COOH (2-hydroxypropanoic acid or lactic acid)
This is how you convert Ethanol into 2-hydroxypropanoic acid.
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