Question

how to convet CH3CH2CL into CH3CH2CH2NH2​

Answer 1

.. ..................................

this follows SN2 mechanism

Answer 2

Answer:

Ethyl chloride on treatment with alcoholic KCN forms propane nitrile which on reduction with LiAlH₄ forms propylamine.

Explanation:

The reduction of cyanides into primary amine provides an excellent method to convert an alkyl halide into an amine having one more carbon atom and is thus very useful in the ascent of the series.

The general reaction is shown below.

RX + KCN (alc) → R-C≡N + 4H → R-CH₂NH₂

• Alkyl halide on reaction with alcoholic KCN  form alkyl cyanide.

• Amines can be prepared by the reduction of the corresponding cyanides(nitriles) with LiAlH₄, Na/C₂H₅OH or with hydrogen in the presence of Raney nickel.

• CH₃CH₂Cl(ethyl chloride) on reacting with alcoholic KCN forms CH₃CH₂CN(propane nitrile), which on reduction with LiAlH₄, Na/C₂H₅OH or with hydrogen in the presence of Raney nickel forms CH₃CH₂CH₂NH₂(propylamine).

       The conversion is shown below.

       CH₃CH₂Cl + KCN (alc) → CH₃CH₂CN

       CH₃CH₂CN+ 4H → R-CH₂NH₂