Question

how to count divisors

Answer 1

If you to find No. of Divisor or Factor of any number You can follow these steps

We will take Example of 276

1)Prime Factorize the number
276 =
${2}^{2} \times {3}^{1} \times {23}^{1}$
Then no. of factors of 276 = (K+1)(Y+1)(Z+1)
where K ,Y ,Z are the Respective Power of 2 , 3 , 23

Total factor =( 2+1)(1+1)(1+1)
= 12

OR
If X is a number is and it's prime Factorization is
(X^k )×(Y^Q)×(Z^R)×(S^T).......

then Total factor = (K+1)(Q+1)(R+1)(T+1)