how to count no of sigma and pi bond in N2,N2(+),O2,O2(+)
explain it clearly and if there is any trick then explain trick also
Answers
1. there two pi bonds and one sigma bond in N2. .
reason (not confirmed) : N2 is fairly simple; since nitrogen is atomic number 7, it has an electron configuration of 1s22s22p3
, so it favorably shares its three 2
p electrons with three other 2
p electr.ons from another nitrogen to form a noble gas configuration ( 1s22s22p6).
Since all three
2p orbitals participate, we form one 2pz−2pz head-on (σ) interaction, one 2px−2px sidelong (π) interaction, and one 2py−2py sidelong (π) interaction.
Thus, we form a triple bond, which consists of the one (σ
) and two( π) bonds we just mentioned. The remaining two lone pairs of electrons are stored in each nitrogen's 2
s orbital. So, we get the following structure that illustrates this discussion:
3. O2 has 1 sigma bond and 1 pi bond.
reason : the O2 molecule's Lewis structure shows a double bond between the two oxygen atoms. Always remember that a double bond is comprised of 1 sigma bond and 1 pi bond. A triple bond has 1 sigma and 2 pi bonds.
All single bonds will always be a sigma bond
In a double bond one of the bond is always a sigma and other one a pi bond.
In a triple bond one of the bond is sigma and the other two are pi bonds.
No.of sigma bonds =no.of atoms - 1
And no.of pi bonds =no.of bonds - no.of sigma bonds
Answer:
hope it helps u.........
