Physics, asked by anj7, 1 year ago

how to derive mirror formula

Answers

Answered by Anonymous
4
★★★hiii friend!!!!★★★
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■Here is ur questions answer!!

⇒ Mirror formula is the relationship between object distance (u), image distance (v) and focal length.

⇒ 1 upon v+1 upon u=1 upon f

 
■ Now, we have to proof of mirror formula:

⇒ Let in ΔABCΔABC and ΔA′B′C′

√ ΔABCΔABC ∼∼ ΔA′B′CΔA′B′C [AA similarity]
√ AB upon  A′B′=AC upon A′C′ ⋯⋯⋯⋯⋯⋯⋯⋯(1)
√ Similarly, In ΔFPEΔFPEand ΔA′B′F′
√ EP upon A′B′=PF upon A′F
√ AB upon A′B′=PF upon A′F [ AB=EP] ⋯⋯(II)

⇒ now From (i) &(ii)

√ AC upon A′C=PF upon A′F
=>A′C upon AC=A′F upon PF
 
=>(CP−A′P) upon (AP−CP)=(A′P–PF) upon /PF

→ Now, PF=−f;CP=2PF=−2fPF=−f;CP=2PF=−2f ; AP=−uAP=−u ; and A′P=−v

√ Put these value in above relation:

 [(−2f)–(−v)] upon( −u)−(−2f) =[(−v)–(−f)] upon (−f)
 ⟹uv=fv+uf

 ⟹1upon f =1 upon u + 1 upon v

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★★★hope this may help u!!!★★★
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Answered by saikrishna1021
3

Answer:

Here is your answer

Explanation:

U can see the shaded triangle which are congruent

Thank u

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