How to derive newton's third law of motion from second law??????
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Consider an isolated system of 2 bodies A & B. An isolated system means where there is no external force acting.Now let F be the force acting on B by A & F be the force acting on A by B.Now rate of change of momentum of A =dpA/dt and rate of change of momentum of B =dpB/dt
thus FAB=dpB/dt (i)......
FBA=dpA/dt (ii)........
Adding 1 and 2 we get FAB+FBA=dpB/dt+dpA/dt =d(pB+pA)/dt
But if no force is applied momentum will also be 0 because no velocity will be there so rate of change of momentum will also be 0
thus d(pA+pB)/dt=0
therefore FAB+FBA=0
or,FAB=-FBA
(3RD LAW OF MOTION)
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