Question

How to derive second equation of motion from third equation of motion..

Answer 1

go on you tube and see video of edu mantra ..you will understand properly because the sir of that you tube explain very well. hope it will help you....

Answer 2

Answer:

s=ut+1/2at square

1. in graph the area is equal to the distance coverd

we will find the area of on triangle and rec. by adding both we can the sec equation of motion.. if u will see the graph the length of rec =time and breadth =initial velocity

so t*u+area of triangle

area if triangle =1/2*base *height

base of triangle =time

height =final velocity -initial velocity

therefore, s(distance)=ut +1/2t(u-t)

s=ut+1/2t(at+u-u) we can derive this from equ 1.

hence s=ut+1/2 atsquare