how to derive tan75 degrees please answer?
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sin75÷cos75 you will get the answer
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{Tan(A + B) = (TanA + TanB)/(1-TanATanB)}
tan 75° = Tan(45°+ 30°) = (Tan45° + Tan30°)/(1-Tan 45° Tan30°)
tan 75° = (1 + 1 / √3 ) / (1 - 1 /√3)
tan 75° = (√3 + 1 ) / (√3 - 1 )
Hope it helps u.
Thanks, Mafam
Similar questions
tan 75° = Tan(45°+ 30°) = (Tan45° + Tan30°)/(1-Tan 45° Tan30°)
tan 75° = (1 + 1 / √3 ) / (1 - 1 /√3)
tan 75° = (√3 + 1 ) / (√3 - 1 )
Hope it helps u.