How to derive the equation v2 − u2 = 2aS? I know how to get the other equations of motion.
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S = Area of Rectangle + Area of Triangle
S = ut + 1/2(v - u)(t)
(Substituting t = (v - u)a, from first equation of motion)
S = u(v - u)/a + 1/2(v - u)(v - u)/a
Rearranging the terms,
v2 = u2 + 2aS
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