How to derive the formular I1=IR1/R1+R2
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Answered by
18
there are two resistances. R1 and R2 connected in paralle. There is a battery of potential V connected in parallel with both resistances.
current in the R1 : = i1 = V/R1
current in R2: I2 = V / R2
So total current from battery = I = V (1/R1 + 1/R2) = V (R1+R2)/R1R2
So we get I1 = R2 I / (R1 + R2)
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If the two resistance are in series, I1 = I2 = I.
current in the R1 : = i1 = V/R1
current in R2: I2 = V / R2
So total current from battery = I = V (1/R1 + 1/R2) = V (R1+R2)/R1R2
So we get I1 = R2 I / (R1 + R2)
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If the two resistance are in series, I1 = I2 = I.
Answered by
6
Consider the current in R1 and R2 as I1 and I2.
Voltage across R1 is
V1=I1×R1
The equivalent resistance of circuit is
R=R1×R2/(R1+R2)
Total voltage of circuit is
V=I×R
But since the resistances are in parallel the voltage across R1 and R2 is same as supply voltage V.
Equating V and V1
I×R=I1×R1
I×R1×R2/(R1+R2)=I1×R1
Thus
I1=I×R2/(R1+R2)
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