How to derive the:
Lens formula and Mirror formula.
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its in ur science book u can see it
Mayank972:
I know the formula but from how the formula is derived i want to know that
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Mirror formula is the relationship between object distance (u), image distance (v) and focal length.
Derivation
_______________
The figure shows an object AB at a distance u from the pole of a concave mirror. The image A1B1 is formed at a distance v from the mirror. The position of the image is obtained by drawing a ray diagram.
Consider the D A1CB1 and D ACB
[when two angles of D A1CB1 and D ACB are equal then the third angle
But ED = AB
From equations (1) and (2)
If D is very close to P then EF = PF
But PC = R, PB = u, PB1 = v, PF = f
By sign convention
PC = -R, PB = -u, PF = -f and PB1 = -v
Equation (3) can be written as
Dividing equation (4) throughout by uvf we get
Equation (5) gives the mirror formula
Derivation of Lens Formula (Convex Lens )
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed beyond 2F2 and is real and inverted.
OA = Object distance = u
OA1 = Image distance = v
OF2 = Focal length = f
OAB and OA1B1 are similar
But we know that OC = AB
the above equation can be written as
From equation (1) and (2), we get
Dividing equation (3) throughout by uvf
Derivation of Lens Formula (Concave Lens)
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed between O and F1 on the same side as the object is kept and the image is erect and virtual.
HOPE THIS HELPSS :) :)
plzz mark it as branliest:-)
Derivation
_______________
The figure shows an object AB at a distance u from the pole of a concave mirror. The image A1B1 is formed at a distance v from the mirror. The position of the image is obtained by drawing a ray diagram.
Consider the D A1CB1 and D ACB
[when two angles of D A1CB1 and D ACB are equal then the third angle
But ED = AB
From equations (1) and (2)
If D is very close to P then EF = PF
But PC = R, PB = u, PB1 = v, PF = f
By sign convention
PC = -R, PB = -u, PF = -f and PB1 = -v
Equation (3) can be written as
Dividing equation (4) throughout by uvf we get
Equation (5) gives the mirror formula
Derivation of Lens Formula (Convex Lens )
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed beyond 2F2 and is real and inverted.
OA = Object distance = u
OA1 = Image distance = v
OF2 = Focal length = f
OAB and OA1B1 are similar
But we know that OC = AB
the above equation can be written as
From equation (1) and (2), we get
Dividing equation (3) throughout by uvf
Derivation of Lens Formula (Concave Lens)
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed between O and F1 on the same side as the object is kept and the image is erect and virtual.
HOPE THIS HELPSS :) :)
plzz mark it as branliest:-)
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