Question

how to derive the third equations of motion using the graphical method??​

Answer 1

Answer:

• Derivation of Third Equation of Motion by Graphical Method

S = ½ (Sum of Parallel Sides) × Height.

S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...

S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...

S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.

S= ½ (v+u) × (v-u)/a.

• S = (v2-u2)/2a

Answer 2

Explanation:

Derivation of Third Equation of Motion by Graphical Method

S = ½ (Sum of Parallel Sides) × Height.

S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...

S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...

S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.

S= ½ (v+u) × (v-u)/a.

S = (v2-u2)/2a.

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