How to determine bond order for special cases?
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hey friend here is your answer
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Generally, bond order is determined by molecular orbit theory.
the formulae is 1/2(Nb - Na)
......[where Nb is the no of bonding electrons. and Na is the no of antibonding electrons.]
in this process you have to sketch the M.O e- configuration and from this you have to count the bonding electrons and antibonding electrons.
for special cases,
it is difficult to determine the M.O e- configuration, then it is solved by resonance.
the formulae of B.O is =
(no of bonds of cononical forms)/(total no of cononical form)
example.... in case of ozone (O3) there are 2 possible cononical forms are there and no of bond is 3. so the B.O is 3/2 =1.5
_______________________________
hope it helps you.☺️☺️✌️✌️
Mark as brainliest❤️❤️❤️❤️
______________________________
Generally, bond order is determined by molecular orbit theory.
the formulae is 1/2(Nb - Na)
......[where Nb is the no of bonding electrons. and Na is the no of antibonding electrons.]
in this process you have to sketch the M.O e- configuration and from this you have to count the bonding electrons and antibonding electrons.
for special cases,
it is difficult to determine the M.O e- configuration, then it is solved by resonance.
the formulae of B.O is =
(no of bonds of cononical forms)/(total no of cononical form)
example.... in case of ozone (O3) there are 2 possible cononical forms are there and no of bond is 3. so the B.O is 3/2 =1.5
_______________________________
hope it helps you.☺️☺️✌️✌️
Mark as brainliest❤️❤️❤️❤️
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