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How to determine the number of Geometrical Isomers and optical Isomers with polydentide ligands?
Easy and tricks needed
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Answers
Answered by
7
Answer:
For Ma2b2c2, you could go by:
All cis (aCa) (bCb) (cCc)
All trans (aTa) (bTb) (cTc)
Only 1 trans (aTa)
Only 1 trans (bTb)
Only 1 trans (cTc)
Similar cases could be done for M(AA)b2c2, except of the fact that, (AA) will remain always cis [all cases EXCEPT where the 2 donor atoms are connected by NOT-A-VERY-LONG-CHAIN]
Answered by
1
Answer:
Hope its help u............xd
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