Question

How to differentiate d/dt*3tcube​

Answer 1

Step-by-step explanation:

ᴅ(~)/ᴅᴛ ɪꜱ ᴀɴ ᴏᴘᴇʀᴀᴛᴏʀ ᴛᴏ ᴍᴇᴀɴ "ᴅɪꜰꜰᴇʀᴇɴᴛɪᴀᴛᴇ ᴇᴠᴇʀʏᴛʜɪɴɢ ɪɴ ᴛʜᴇ ( )" ᴏʀ, ᴍᴏʀᴇ ᴄᴏɴᴄᴇᴘᴛᴜᴀʟʟʏ, "ꜱʜᴏᴡ ᴀ ꜱᴍᴀʟʟ ᴄʜᴀɴɢᴇ ɪɴ ᴡʜᴀᴛ'ꜱ ɪɴ ᴛʜᴇ ( ) ᴡɪᴛʜ ʀᴇꜱᴘᴇᴄᴛ ᴛᴏ ᴀ ꜱᴍᴀʟʟ ᴄʜᴀɴɢᴇ ɪɴ ᴛɪᴍᴇ." ᴛʜᴇ ᴛʜɪɴɢ ʙᴇɪɴɢ ᴏᴘᴇʀᴀᴛᴇᴅ ᴏɴ ᴄᴀɴ ʙᴇ ᴀ ᴠᴀʀɪᴀʙʟᴇ ʟɪᴋᴇ ᴠ ʙᴜᴛ ɪᴛ ᴄᴀɴ ᴀʟꜱᴏ ʙᴇ ɪᴛꜱ ᴏᴡɴ ꜰᴏʀᴍᴜʟᴀ ᴡɪᴛʜ ꜱᴇᴠᴇʀᴀʟ ᴛᴇʀᴍꜱ ᴀɴᴅ ᴠᴀʀɪᴀʙʟᴇꜱ ɪɴ ɪᴛ.

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ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ᴜʜ...ᴍᴀʀᴋ ɪᴛ ᴀꜱ ʙʀᴀɪɴɪᴇꜱᴛ ᴘʟᴇᴀꜱᴇ..!!

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$⭟THᴀ᭄NK UH..♥️(. ❛ ᴗ ❛.)♡$

Answer 2

ᴅv/dt= maximum rate of change the capacitor

can withstand. To determine the energy content of the waveform (Ko) the following formula is used: Ko=2 ∫ (dv/dt)2dt where dv=change in voltage over time interval. dt= Change in time of the slope section measured. For waveforms with straight edge transitions.