Physics, asked by snpspawankumar, 10 months ago

How to differentiate PV^gamma. Plz only if you know it, then only answer. And plz solve it in copy.
Thank you.​

Answers

Answered by basavaraj5392
0

Answer:

PV^y = Constant. is a adiabatic process, you can differentiate it according to the requirement in the question.

In adiabatic process heat exchange with system and surrounding is zero.

Answered by rahul123437
2

The process is explanation in below.

Given:

PV^{\gamma } = constant process

To find:

How to differentiate PV^{\gamma }

Formula used:

log(a^{b}) = b log(a)

Explanation:

PV^{\gamma } = constant this is the adiabatic reversible process. In this process the heat is not transferred from system to surrounding or surrounding to system

This can be differentiated by using logarithmic formula principle.

From the above formula

log(a^{b}) = b log(a)

log(PV^{\gamma }) = log(constant)

\gamma log(PV) = log(constant)

We can differentiate it with multiplication rule of differentiation.

To learn more....

1)A diatomic ideal gas initially at 273K is given 100cal heat due to which system did 209J work.  

Molar heat capacity (Cm) of gas for the process is :  

(A) 3/2R

(B) 5/2R

(C) 5/4R  

(D) 5R

https://brainly.in/question/7915567

2)An ideal gas is taken through a cycle A-B-C-A as shown in figure.If net heat supplied to the gas in the cycle is 5J the work done by the gas in the process C-A

https://brainly.in/question/7394734

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