how to differentiate this function
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Anonymous:
Is the answer = x + 1
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apply v/u rule
d/dx(v/u)=udv/dx-vdu/dv/v²
df(x)/dx=x(3x²+2x)-(x³+x²+1)(1)/x²
=3x³+2x²-x³-x²-1/x²
=2x³+x²-1/x²
hope this helps
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