Question

how to differentiate y=x2 tanx and y=ex logx

Answer 1

Hey!!!

Here is your answer_____________



we have,
d/dx (u.v) = u.d/dx(v) + v.d/dx(u)


1) y = x^2 tanx

differentiate y with respect to x

dy/dx = x^2.d/dx(tanx) + tanx.d/dx(x^2)

= x^2.(sec^2 x) + tanx.(2x)

=x^2.(sec^2 x) + 2x.tanx


2) y = e^x.(logx)

differentiate y with respect to x

dy/dx = e^x.d/dx(log x) + log x .d/dx(e^x)

= e^x.(1/x) + logx.(e^x)

taking e^x common

= e^x . [ 1/x + log x]


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