How to dilute .1 normalty sulphuric acid into .02normalty sulphuric acid?
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Answer:
By law of dilution,
M1V1 = M2V2
I.e. the product of molarity before dilition and the volume is equal to the product of molarity after dilution and the new volume.
So,
M2= 0.5×1÷10
= 0.05 M
Now normality
= molarity × n factor
= 0.05 × 2
=0.1 N
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