How to divide line segmentof length 7 cm internally in the ratio of 5:3
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Steps of constmction:
1. Draw the line segment AB = 7 cm.
2. Draw ray BX making an acute ∠ABX.
3. Along BX. mark off five points B1, B2, B3, B4 and B5. Join B2 to A.
4. Through B5 draw B5P || B2A, intersecting BA produced at P.
5. The point P so obtained is the required point which divides AB externally in the ratio 3:5.
Proof:In △s ABB2 and PBB5,
B5P || B2A ⇒ ABB2 ~ PBB5
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