how to do both these questions
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[2ⁿ⁺⁴-2(2ⁿ)]/[2(2ⁿ⁺³)=(2ⁿ⁺⁴-2ⁿ⁺¹)/2ⁿ⁺⁴ [∵mᵃ×mᵇ=mᵃ⁺ᵇ]
=[(2ⁿ⁺⁴/2ⁿ⁺⁴)-(2ⁿ⁺¹/2ⁿ⁺⁴)]
=1-2⁽ⁿ⁺⁴⁾⁻⁽ⁿ⁺¹⁾ [∵mᵃ/mᵇ=mᵇ⁻ᵃ when,b∠a]
=1-2³
=1-8
=-7
(a+1/a)²=3
⇒a+1/a=√3
cubing on both sides
⇒(a+1/a)³=(√3)³
⇒a³+1/a³+3×a×1/a×(a+1/a)=3√3
⇒a³+1/a³+3(a+1/a)=3√3
⇒a³+1/a³+3√3=3√3
⇒a³+1/a³=0
=[(2ⁿ⁺⁴/2ⁿ⁺⁴)-(2ⁿ⁺¹/2ⁿ⁺⁴)]
=1-2⁽ⁿ⁺⁴⁾⁻⁽ⁿ⁺¹⁾ [∵mᵃ/mᵇ=mᵇ⁻ᵃ when,b∠a]
=1-2³
=1-8
=-7
(a+1/a)²=3
⇒a+1/a=√3
cubing on both sides
⇒(a+1/a)³=(√3)³
⇒a³+1/a³+3×a×1/a×(a+1/a)=3√3
⇒a³+1/a³+3(a+1/a)=3√3
⇒a³+1/a³+3√3=3√3
⇒a³+1/a³=0
PG1173:
thx bro....it is difficult to understand this in this way.....can u pls write it in page and send a picture of it???
sorry
which step haven't you understand
the whole answer if the first question
*of
just i used the formula a to the power m x a to the power n = a to the power m+n.
okay.....thank you
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