how to do by method.
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Length of the box formed = 48 - 2*8
= 48 - 16
= 32 cm
Width of the box formed = 36 - 2*8
= 36 - 16
= 20 cm
Height of the box = 8 cm
Volume = Length *Width *Height
= 32 * 20 * 8
= 640*8
= 5120 cm^3
= 48 - 16
= 32 cm
Width of the box formed = 36 - 2*8
= 36 - 16
= 20 cm
Height of the box = 8 cm
Volume = Length *Width *Height
= 32 * 20 * 8
= 640*8
= 5120 cm^3
Answered by
0
Given the length of the metallic sheet = 48cm.
Given that breadth of the metallic sheet = 36cm.
Given that height = 8cm.
Given that from each corner a square of 8cm is cut off. Therefore from the sheet for two sides, a total of 16m(8 + 8) has to be subtracted.
Length = 48 - 16
= 32m.
Breadth = 36 - 16
= 20m.
Therefore volume of the box = l * b * h
= 32 * 20 * 8
= 5120m^3.
Therefore the volume of the box = 5120cm^3.
Hope this helps!
Given that breadth of the metallic sheet = 36cm.
Given that height = 8cm.
Given that from each corner a square of 8cm is cut off. Therefore from the sheet for two sides, a total of 16m(8 + 8) has to be subtracted.
Length = 48 - 16
= 32m.
Breadth = 36 - 16
= 20m.
Therefore volume of the box = l * b * h
= 32 * 20 * 8
= 5120m^3.
Therefore the volume of the box = 5120cm^3.
Hope this helps!
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