How to do evaluate with alzebric identities 1 (i) (101)square
Answers
Answered by
2
Answer:
(100+1)^2=100^2+1^2+2×100×1=10000+1+200=10201
Answered by
2
Answer:
10201
Step-by-step explanation:
(101)^2 = (100+1)^2
= (100)^2 + (1)^2+ (2×100×1) [ since, (a+b)^2=a^2+b^2+2×a×b]
= 10000+1+200
= 10201
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