Question

How to do exercise 27

Answer 1

Exercise 27:

Note- For fractions to add/subtract you will need to have the same denominator. So the main steps will be 
1. We need to make the denominator same by using LCM 
2. The last step will be to add up and that's it. 

Solutions. 
1. $\frac{2}{5}$ + $\frac{3}{10}$
LCM of 5 and 10 = 5×2 = 10 
⇒ $\frac{2}{5}$ =  $\frac{2*2}{5*2}$ = $\frac{4}{10}$ 
⇒  $\frac{4}{10}$ + $\frac{3}{10}$ = $\frac{7}{10}$

2. $\frac{4}{7}$ + $\frac{2}{3}$ 
LCM of 7 and 3 = 7×3 = 21
⇒ $\frac{4}{7}$ =  $\frac{4*3}{7*3}$ = $\frac{12}{21}$
⇒ $\frac{2}{3}$ =  $\frac{2*7}{3*7}$ = $\frac{14}{21}$
⇒ $\frac{12}{21}$ + $\frac{14}{21} =$ =  $\frac{26}{21}$

3.  $\frac{4}{9}$ + $\frac{5}{6}$  
LCM of 9 and 6 = 3×3×2 = 18
⇒ $\frac{4}{9}$ =  $\frac{4*2}{9*2}$ = $\frac{8}{18}$
⇒ $\frac{5}{6}$ =  $\frac{5*3}{6*3}$ = $\frac{15}{18}$
⇒  $\frac{8}{18}$ + $\frac{15}{18}$ = $\frac{23}{18}$

4.  $\frac{3}{4}$ + $\frac{11}{12}$ 
LCM of 4 and 12 = 2×2×3 = 12
⇒ $\frac{3}{4}$ =  $\frac{3*3}{4*3}$ = $\frac{9}{12}$
⇒ $\frac{11}{12}$ =  $\frac{11}{12}$ = $\frac{11}{12}$
 $\frac{9}{12}$ + $\frac{11}{12}$ = $\frac{18}{12}$

5. $\frac{5}{12}$ + $\frac{7}{16}$  
LCM of 12 and 16 = 12 × 16 = 48
⇒ $\frac{5}{12}$ =  $\frac{5*4}{12*4}$ = $\frac{20}{48}$
⇒ $\frac{7}{16}$ =  $\frac{7*3}{16*3}$ = $\frac{21}{48}$
[/tex] = $\frac{20}{48}$ + $\frac{21}{48}$ = $\frac{41}{48}$

Answer 2

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