Question

How to do factorization of algebraic expressions?

Answer 1

(x2 + 1)(x + 1)(x - 1)

If we simplify this expression, we get:

(x2 + 1)(x2 + x - x - 1)
(x2 + 1)(x2 - 1)
(x4 + x2 - x2 - 1)
x4 - 1

Now you should recognize this expression as a difference between two squares. Using the technique presented in the Difference Between Two Squares lesson, we can factor this into

(x2 + 1)(x2 - 1)

the above factors are equal to (x2 + 1)(x + 1)(x - 1)

Answer 2

first answering this qurstions you need to know the square or cube formulae

i am giving u an examplevof factorisation of a square formulae


x2+4xy+4
x2+2.x.2+2 square. (now what i am writing in this bracket,u do nt need to write just to show u how i have done this ,so first let the x2 term be a the 4 term be b ,so now we have to make the middle term that is 4xy in the form of 2ab ,so i have written the furst term as x square and made the lasr term as 2 square that is 4 because 2×2 that is 2 square is 4 ,so now i have written the middle term as 2×x×2,because i want to make it in the form of 2ab)
(x+2)square _(as formulae )
(x+2)×(x+2)


so this is how you have to do the factorisation of algebraic expression