How to do HCF of 91 112 49
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49)91(1
-49
-–---------
42)49(1
-42
----------------
7)42(6
- 42
--------------------
0
by dividing 112 by 7 we get
7)112(16
-112
--------
0
Therefore hcf is the last divisot I.e..7
49)91(1
-49
-–---------
42)49(1
-42
----------------
7)42(6
- 42
--------------------
0
by dividing 112 by 7 we get
7)112(16
-112
--------
0
Therefore hcf is the last divisot I.e..7
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