How to do middle term splitting in algebra?
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Answered by
1
perhaps it is the quadratic expression factorization problem.
a x² + b x + c
Find factors of product a * c.. in such a way that their sum is - b
x² - 5 x + 4
factors or 1 * 4 = 1, 2, 4. choose 1 and 4
split the middle term as - 4 x and - x
X² - 4 x - x + 4
X (X - 4) - 1 (X - 4)
(X-1) (X-4)
==========================
2 x² + x - 10
factors of 2 * -10 are 1, 2, 3, 4, 5, 10, 20, -1, -2, -4, -5, -10, -20
If u add -4 and 5 you get +1.
2 x² - 4 x + 5 x - 10
2 x ( x -2) + 5 ( x - 2) => (2 x + 5 ) ( x - 2 )
a x² + b x + c
Find factors of product a * c.. in such a way that their sum is - b
x² - 5 x + 4
factors or 1 * 4 = 1, 2, 4. choose 1 and 4
split the middle term as - 4 x and - x
X² - 4 x - x + 4
X (X - 4) - 1 (X - 4)
(X-1) (X-4)
==========================
2 x² + x - 10
factors of 2 * -10 are 1, 2, 3, 4, 5, 10, 20, -1, -2, -4, -5, -10, -20
If u add -4 and 5 you get +1.
2 x² - 4 x + 5 x - 10
2 x ( x -2) + 5 ( x - 2) => (2 x + 5 ) ( x - 2 )
Answered by
0
a x² + b x + c
Multiply a and c in such a way that we got the sum b .
Multiply a and c in such a way that we got the sum b .
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