Math, asked by rahulraja7893, 4 months ago

How to do pls help its the 6th sum

Attachments:

Answers

Answered by Anuchand146
5

\green{\star Verified\: Answer}

\blue\huge{\star Answer\star}

Consider the ΔPQR. PRS is the exterior angle and QPR and PQR are interior angles.

So, PRS = QPR+PQR (According to triangle property)

Or, PRS -PQR = QPR ———–(i)

Now, consider the ΔQRT,

TRS = TQR+QTR

Or, QTR = TRS-TQR

We know that QT and RT bisect PQR and PRS respectively.

So, PRS = 2 TRS and PQR = 2TQR

Now, QTR = ½ PRS – ½PQR

Or, QTR = ½ (PRS -PQR)

From (i) we know that PRS -PQR = QPR

So, QTR = ½ QPR (hence proved).

Answered by ananya4826
0

Refer the above pic

Step-by-step explanation:

Plzz mark me brainliest

Attachments:
Similar questions