Math, asked by ss2007, 6 months ago

How to do Q10

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Answered by choudharyadarsh777
0

Step-by-step explanation:

Given, sum of L²+B²+H²=48

Multiply both sides with 2,

2(L²+B²+H²)=2(48) ...........(I)

TSA of cuboid = 2(LB+BH+LH)=96 ..........(II)

Subtracting equation (II) from equation (I),

2(L²+B²+H²)-2(LB+BH+LH) = 2(48) - 96

(L²+B²-2LB)+(B²+H²-2BH)+(H²+L²-2LH) = 0

(L-B)²+(B-H)²+(H-L)² = 0

So L=B, B=H, H=L

We can conclude that L=B=H

Putting the value in equation (I),

3H² = 48 cm²

H² = 16 cm²

H = 4 cm

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