Question

How to do q9 2nd part

Answer 1

alpha^2/beta + beta^2/alpha

LCM-> alpha*beta

so,

alpha^3+beta^3/alpha*beta

now, using the identity

(alpha+beta)^3-3alpha*beta(alpha+beta)/alpha*beta

now,

alpha+beta=-b/a

alpha*beta=c/a

putting up the values

(-b/a)^3-3*c/a(-b/a) / c/a

-b^3/a^3+bc/a^2 / c/a
-b^3/a^3+bc/a^2*a/c

Answer 2

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