Question

how to do the HCF of 12 and 28

Answer 1

Here is your answer mate,

Here, 28>12, thus, a=28 and b=12

By using Euclid's Division Lemma,

a=bq+r, 0 is less than or qual to r less than b

ie; 28 = 12*2+4

Since r is not equal to 0, 12 = 4*3+0

Now, r = 0. Therefore HCF of 12 and 28 is 4

Hope it helps you..

Answer 2

Prime factorisation of 12 and 28 gives:
28 = 2×2×7
12 = 2×2×3
Therefore, the smallest power of the common factors 2 ×2 ,respectively .

HCF (12,28) = 2 ×2= 4

Hope you understand..........!!